# FAA-H-8083-30B Aviation Maintenance Technician Handbook — General # Chapter 3: Mathematics in Aviation Maintenance Source: FAA-H-8083-30B Aviation Maintenance Technician Handbook — General, Chapter 3. Page markers like [General p. 3-5] give the handbook page number. [General p. 3-1] ## Introduction Mathematics is woven into many areas of everyday life. Performing mathematical calculations with success requires an understanding of the correct methods, procedures, practice, and review of these principles. Mathematics may be thought of as a set of tools. The aviation mechanic needs these tools to successfully complete the maintenance, repair, installation, or certification of aircraft equipment. Many examples of using mathematical principles by the aviation mechanic are available. Tolerances in turbine engine components are critical, making it necessary to measure within a ten-thousandth of an inch. Because of these close tolerances, it is important that the aviation mechanic can make accurate measurements and mathematical calculations. An aviation mechanic working on aircraft fuel systems also uses mathematical principles to calculate volumes and capacities of fuel tanks. The use of fractions and surface area calculations are required to perform sheet metal repair on aircraft structures. ## Whole Numbers Whole numbers are the numbers 0, 1, 2, 3, 4, 5, and so on. Whole numbers can be thought of as counting numbers. ### Addition of Whole Numbers Addition is the process where the value of one number is added to the value of another. The result is called the sum. When working with whole numbers, it is important to understand the principle of the place value. The place value in a whole number is the value of the position of each individual digit within the entire number. For example, in the number 512, the 5 is in the hundreds column, the 1 is in the tens column, and the 2 is in the ones column. Examples of place values of three whole numbers are shown in Figure 3-1. When adding several whole numbers, such as 4,314, 122, 93,132, and 10, align them into columns according to place value and then add. 4,314 122 93,132 + 10 97,578 Therefore, 97,578 is the sum of the four whole numbers. ### Subtraction of Whole Numbers Subtraction is the process where the value of one number is taken from the value of another. The result is called the difference. When subtracting two whole numbers, such as 3,461 from 97,564, align them into columns according to place value and then subtract. 97,564 – 3,461 94,103 The difference of the two whole numbers is 94,103. ### Multiplication of Whole Numbers Multiplication is the process of repeated addition. For example, 4 × 3 is the same as 4 + 4 + 4. The result is called the product. Example: How many hydraulic system filters do you have if there are 35 cartons in the supply room and each carton contains 18 filters? 18 × 35 90 54 630 Therefore, there are 630 filters in the supply room. ### Division of Whole Numbers Division is the process of finding how many times one number (called the divisor) is contained in another number (called the dividend). The result is the quotient, and any amount left over is called the remainder. quotient divisor dividend Example: 218 landing gear bolts need to be divided between 7 aircraft. How many bolts will each aircraft receive? [General p. 3-2] 31 7 218 −21 8 −7 1 In this case, there are 31 bolts for each of the seven aircraft with one extra remaining. ## Fractions A fraction is a number written in the form N⁄D where N is called the numerator and D is called the denominator. The fraction bar between the numerator and denominator shows that division is taking place. 17 , 2 , 5 Some examples of fractions are: 18 3 8 The denominator of a fraction cannot be a zero. For example, the fraction 2⁄0 is not allowed, because dividing by zero is undefined. An improper fraction is a fraction in which the numerator is equal to or larger than the denominator. For example, 4⁄4 or ### Finding the Least Common Denominator To add or subtract fractions, they must have a common denominator. In math, the least common denominator (LCD) is generally used. One way to find the LCD is to list the multiples of each denominator and then choose the smallest number that they all have in common (can be divided by). Example: Add 1⁄5 + 1⁄10 by finding the LCD. Multiples of 5 are: 5, 10, 15, 20, 25, and so on. Multiples of 10 are: 10, 20, 30, 40, and so on. Notice that 10, 20, and 30 are in both lists, but 10 is the smallest or LCD. The advantage of finding the LCD is that the final answer should be in the simplest form. A common denominator can also be found for any group of fractions by multiplying all the denominators together. This number is not always the LCD, but it can still be used to add or subtract fractions. Example: Add 2⁄3 + 3⁄5 + 4⁄7 by finding a common denominator. A common denominator can be found by multiplying the denominators 3 × 5 × 7 to get 105. 3 5 7 105 105 105 105 105 ### Addition of Fractions In order to add fractions, the denominators must be the same number. This is referred to as having “common denominators.” Example: Add 1⁄7 to 3⁄7 1 + 3 = 1 + 3 = 4 7 7 7 7 If the fractions do not have the same denominator, then one or all the denominators must be changed so that every fraction has a common denominator. Example: Find the total thickness of a panel made from coating. To add these fractions, determine a common denominator. The LCD for this example is 1, so only the first fraction must be changed since the denominator of the second fraction is already in 64ths. 7 32 64 32 × 2 64 64 64 64 64 Therefore, 7⁄64 is the total thickness. ### Subtraction of Fractions To subtract fractions, they must have a common denominator. Example: Subtract 2⁄17 from 10⁄17 10 – 2 = 10 – 2 = 8 17 17 17 17 If the fractions do not have the same denominator, then one or all the denominators must be changed so that every fraction has a common denominator. *Figure 3-1. Example of place values of whole numbers.* Figure labels: 15⁄8 are examples of improper fractions.; 3⁄32‑inch thick aluminum, that has a 1⁄64-inch thick paint; Place Value; 35 shown as; 269 shown as; 12,749 shown as [General p. 3-3] Example: The tolerance for rigging the aileron droop of an airplane is 7⁄8 inch ± 1⁄5 inch. What is the minimum droop to which the aileron can be rigged? To subtract these fractions, first change both to common denominators. The common denominator in this example is 40. Change both fractions to 8 5 8 × 5 5 × 8 40 40 40 40 Therefore, 27⁄40 is the minimum droop. ### Multiplication of Fractions Multiplication of fractions does not require a common denominator. To multiply fractions, first multiply the numerators. Then, multiply the denominators. Example: 3 × 7 × 1 = 3 × 7 × 1 = 21 5 8 2 5 × 8 × 2 80 The use of cancellation when multiplying fractions is a helpful technique. Cancellation divides out or cancels all common factors that exist between the numerators and denominators. When all common factors are cancelled before the multiplication, the final product is in the simplest form. Example: 2 1 = 2 15 7 15 7 5 × 1 5 5 1 ### Division of Fractions Division of fractions does not require a common denominator. To divide fractions, first change the division symbol to multiplication. Next, invert the second fraction. Then, multiply the fractions. Example: Divide 7⁄8 by 4⁄3 = 21 8 3 8 4 8 × 4 32 Example: In Figure 3-2, the center of the hole is in the center of the plate. Find the distance that the center of the hole is from the edges of the plate. To find the answer, the length and width of the plate should each be divided in half. First, change the mixed numbers to improper fractions: 5 7⁄16 inches = 87⁄16 inches 3 5⁄8 inches = 29⁄8 inches Then, divide each improper fraction by 2 to find the center of the plate. 87 ÷ 2 = 87 × 1 = 87 inches 16 1 16 2 32 29 ÷ 2 = 29 × 1 = 29 inches 8 1 8 2 16 Finally, convert each improper fraction to a mixed number: 87 = 87 ÷ 32 = 2 23 inches 32 32 29 = 29 ÷ 16 = 1 13 inches 16 16 Therefore, the distance to the center of the hole from each of the plate edges is 2 23⁄32 inches and 1 13⁄16 inches. ### Reducing Fractions A fraction needs to be reduced when it is not in the simplest form or “lowest terms.” Lowest term means that the numerator and denominator do not have any factors in common. That is, they cannot be divided by the same number (or factor). To reduce a fraction, determine what the common factor(s) are and divide these out of the numerator and denominator. For example, when both the numerator and denominator are even numbers, they can both be divided by 2. Example: The total travel of a jackscrew is 13⁄16 inch. If the travel in one direction from the neutral position is 7⁄16 inch, what is the travel in the opposite direction? 13 – 7 = 13 – 7 = 6 16 16 16 16 The fraction 6⁄16 is not in lowest terms because the numerator (6) and the denominator (16) have a common factor of 2. To reduce 6⁄16, divide the numerator and the denominator by 2. The final reduced fraction is 3⁄8 as shown below. 6 = 6 ÷ 2 = 3 16 16 ÷ 2 8 Therefore, the travel in the opposite direction is 3⁄8 inch. ## Mixed Numbers A mixed number is a combination of a whole number and a fraction. Figure labels: 1⁄40, as shown, then subtract. [General p. 3-4] ### Addition of Mixed Numbers To add mixed numbers, add the whole numbers together. Then add the fractions together by finding a common denominator. The final step is to add the sum of the whole numbers to the sum of the fractions for the final answer. Example: The cargo area behind the rear seat of a small airplane can handle solids that are 4 3⁄4 feet long. If the rear seats are removed, then 2 1⁄3 feet is added to the cargo area. What is the total length of the cargo area when the rear seats are removed? = 6 13 = 4 3 4 3 12 12 12 7 1 feet of cargo room 12 ### Subtraction of Mixed Numbers To subtract mixed numbers, find a common denominator for the fractions. Subtract the fractions from each other. It may be necessary to borrow from the larger whole number when subtracting the fractions. Subtract the whole numbers from each other. The final step is to combine the final whole number with the final fraction. Example: What is the length of the grip of the bolt shown in Figure 3-3? The overall length of the bolt is 3 1⁄2 inches, the shank length is 3 1⁄8 inches, and the threaded portion is 15⁄16 inches long. To find the grip, subtract the length of the threaded portion from the length of the shank. 31⁄8 inches – 15⁄16 inches = grip length To subtract, start with the fractions. Borrowing is necessary because 5⁄16 is larger than 1⁄8 (or 2⁄16). From the whole number 3, borrow 1, which is actually 16⁄16. After borrowing, the first mixed number is now 2 18⁄16. This is because, 3 1⁄8 = 3 2⁄16 = 2 + 1 + 2⁄16 = 2 + 16⁄16 + 2⁄16 = 2 18⁄16. 3 1 –1 5 = 3 2 –1 5 = 2 18 –1 5 = 113 8 16 16 16 16 16 16 Therefore, the grip length of the bolt is 113⁄16 inches. (Note: The value for the overall length of the bolt was given in the example, but it was not needed to solve the problem. This type of information is sometimes referred to as a “distracter,” because it distracts from the information needed to solve the problem.) ## The Decimal Number System ### Origin and Definition The number system that we use every day is called the decimal system. The prefix in the word decimal, dec, is a Latin root for the word “ten.” The decimal system probably originated from the fact that we have ten fingers (or digits). The decimal system has ten digits: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. The decimal system is a base 10 system and has been in use for over 5,000 years. A decimal is a number with a decimal point. For example, 0.515, 0.10, and 462.625 are all decimal numbers. Like whole numbers, decimal numbers also have place value. The place values are based on powers of 10, as shown in Figure 3-4. ### Addition of Decimal Numbers To add decimal numbers, they must first be arranged so that the decimal points are aligned vertically and according to place value. That is, adding tenths with tenths, ones with ones, hundreds with hundreds, and so forth. Example: Find the total resistance for the circuit diagram shown in Figure 3-5. The total resistance of a series circuit is equal to the sum of the individual resistances. To find the total resistance, RT, the individual resistances are added together. RT = 2.34 + 37.5 + 0.09 Arrange the resistance values in a vertical column so that the decimal points are aligned and then add. 2.34 37.5 + 0.09 39.93 Therefore, the total resistance, RT = 39.93 ohms. ### Subtraction of Decimal Numbers To subtract decimal numbers, they must first be arranged so that the decimal points are aligned vertically and according to place value. That is, subtracting tenths from tenths, ones *Figure 3-2. Center hole of the plate.* [General p. 3-5] from ones, hundreds from hundreds, and so forth. Example: A series circuit containing two resistors has a total resistance (RT) of 37.272 ohms. One of the resistors (R1) has a value of 14.88 ohms. What is the value of the other resistor (R2)? R2 = RT – R1 = 37.272 – 14.88 Arrange the decimal numbers in a vertical column so that the decimal points are aligned and then subtract. 37.272 –14.88 22.392 Therefore, the second resistor, R2 = 22.392 ohms. ### Multiplication of Decimal Numbers To multiply decimal numbers, vertical alignment of the decimal point is not required. Instead, align the numbers to the right in the same way that whole numbers are multiplied (with no regard to the decimal points or place values) and then multiply. The last step is to place the decimal point in the correct place in the answer. To do this, count the number of decimal places in each of the numbers, add the total, and then assign that number of decimal places to the result. Example: To multiply 0.2 × 6.03, arrange the numbers vertically and align them to the right. Multiply the numbers, ignoring the decimal points for now. 6.03 × 0.2 1206 (ignore the decimal points, for now) After multiplying the numbers, count the total number of decimal places in both numbers. For this example, 6.03 has 2 decimal places and 0.2 has 1 decimal place. Together there are a total of 3 decimal places. The decimal point for the answer is placed 3 decimal places from the right. Therefore, the answer is 1.206. 6.03 2 decimal places × 0.2 1 decimal place 1.206 3 decimal places Example: Using the formula watts = amperes × voltage, what is the wattage of an electric drill that uses 9.45 amperes from a 120-volt source? Align the numbers to the right and multiply. After multiplying the numbers, count the total number of decimal places in both numbers. For this example, 9.45 has 2 decimal places and 120 has no decimal place. Together there are 2 decimal places. The decimal point for the answer is placed 2 decimal places from the right. Therefore, the answer is 1,134.00 watts, or simplified to 1,134 watts. 9.45 2 decimal places × 120 no decimal place 000 1890 + 945 1,134.00 2 decimal places *Figure 3-3. Bolt dimensions.* *Figure 3-4. Place values.* *Figure 3-5. Circuit diagram.* Figure labels: Place Value; 1,623,051; 0.0531; 32.4; 2.34 Ohms; Shank; Grip; 37.5 Ohms; .09 Ohms; Overall length [General p. 3-6] ### Division of Decimal Numbers Division of decimal numbers is performed the same way as whole numbers, unless the divisor is a decimal. quotient divisor dividend When the divisor is a decimal, it must be changed to a whole number before dividing. To do this, move the decimal in the divisor to the right until there are no decimal places. At the same time, move the decimal point in the dividend to the right the same number of places. Then divide. The decimal in the quotient is placed directly above the decimal in the dividend. Example: Divide 0.144 by 0.12 1.2 0.12 0.144 = 12. 14.4 – 12 24 –24 0 Move the decimal in the divisor (0.12) two places to the right. The result is 12.0. Next, move the decimal in the dividend (0.144) two places to the right. The result is 14.4. Now divide. The result is 1.2. Example: The wing area of an airplane is 262.6 square feet and its span is 40.4 feet. Find the mean chord of its wing using the formula: area ÷ span = mean chord. 6.5 40.4 262.6 = 404. 2626.0 – 2424 2020 – 2020 0 Move the decimal in the divisor (40.4) one place to the right. Next, move the decimal in the dividend (262.6) one place to the right. Then divide. The mean chord length is 6.5 feet. ### Rounding Off Decimal Numbers Occasionally, it is necessary to round off a decimal number to some value that is practical to use. For example, a measurement is calculated to be 29.4948 inches. To use this measurement, we can use the process of “rounding off.” A decimal is “rounded off” by keeping the digits for a certain number of places and discarding the rest. The degree of accuracy desired determines the number of digits to be retained. When the digit immediately to the right of the last retained digit is 5 or greater, round up by 1. When the digit immediately to the right of the last retained digit is less than 5, leave the last retained digit unchanged. Example: An actuator shaft is 2.1938 inches in diameter. Round to the nearest tenth. The digit in the tenths column is a 1. The digit to the right of the 1 is a 9. Since 9 is greater than or equal to 5, “round up” the 1 to a 2. Therefore, 2.1938 rounded to the nearest tenth is 2.2. Example: The outside diameter of a bearing is 3.1648 centimeters. Round to the nearest hundredth. The digit in the hundredths column is a 6. The digit to the right of the 6 is a 4. Since 4 is less than 5, do not round up the 6. Therefore, 3.1648 to the nearest hundredth is 3.16. Example: The length of a bushing is 3.7487 feet. Round to the nearest thousandth. The digit in the thousandths column is an 8. The digit to the right of the 8 is a 7. Since 7 is greater than or equal to 5, “round up” the 8 to a 9. Therefore, 3.7487 to the nearest thousandth is 3.749. ### Converting Decimal Numbers to Fractions To change a decimal number to a fraction, “read” the decimal out loud, and then write it into a fraction just as it is read as shown below. Example: One oversized rivet has a diameter of 0.52 inches. Convert 0.52 to a fraction. The decimal 0.52 is read as “fifty-two hundredths.” 0.52 = 52 “fifty-two” 100 “hundredths” In the above fraction of 52⁄100, we can divide 4 into each number resulting in a fraction of 13⁄25. A dimension often appears in a maintenance manual or on a blueprint as a decimal instead of a fraction. To use the dimension, it may need to be converted to a fraction. An aviation mechanic frequently uses a steel rule that is calibrated in units of 1⁄64 of an inch. To change a decimal to the nearest equivalent common fraction, multiply the decimal by 64. The product of the decimal and 64 is the numerator of the fraction and 64 is the denominator. Reduce the fraction, if needed. [General p. 3-7] Example: The width of a hex head bolt is 0.3123 inches. Convert the decimal 0.3123 to a common fraction to decide which socket would be the best fit for the bolt head. First, multiply the 0.3123 decimal by 64: 0.3123 × 64 = 19.9872 Next, round the product to the nearest whole number: 19.98722 ≈ 20. Use this whole number (20) as the numerator and 64 as the denominator: 20⁄64. Now, reduce 20⁄64 to 5⁄16 as 4 is common to both the numerator and denominator. Therefore, the correct socket would be the Example: When accurate holes of uniform diameter are required for aircraft structures, they are first drilled approximately 1⁄64 inch undersized and then reamed to the final desired diameter. What size drill bit should be selected for the undersized hole if the final hole is reamed to a diameter of 0.763 inches? First, multiply the 0.763 decimal by 64. 0.763 × 64 = 48.832 Next, round the product to the nearest whole number: 48.832 ≈ 49. Use this number (49) as the numerator and 64 as the denominator: 49⁄64 is the closest fraction to the final reaming diameter of 0.763 inches. To determine the drill size for the initial undersized hole, subtract 1⁄64 inch from the finished hole size. 49 – 1 = 48 = 3 64 64 64 4 Therefore, a 3⁄4-inch drill bit should be used for the initial undersized holes. ### Converting Fractions to Decimals To convert any fraction to a decimal, simply divide the top number (numerator) by the bottom number (denominator). Every fraction has an approximate decimal equivalent. Example: 0.5 1 1 2 = 1 ÷ 2 = 2 1.0 Therefore, = 0.5 2 – 1.0 0 0.375 3 3 8 = 3 ÷ 8 = 8 3.000 Therefore, = 0.375 8 – 24 60 – 56 40 – 40 0 Calculator tip: numerator (top number) ÷ denominator (bottom number) = the decimal equivalent of the fraction. Some fractions when converted to decimals produce a repeating decimal. Example: 0.33 1 3 = 1 ÷ 3 = 3 1.00 = 0.3 or 0.33 – 9 This decimal can be represented with a bar, or can 10 be rounded. (A bar indicates – 9 that the number(s) beneath it 1 are repeated to infinity.) Other examples of repeating decimals: 0.212121… = 0.21 0.6666… = 0.7 or 0.67 0.254254… = 0.254 ### Decimal Equivalent Chart Figure 3-6 is a fraction to decimal to millimeter equivalency chart. Measurements starting at 1⁄64 inch and up to 3 inches have been converted to decimal numbers and to millimeters. ## Ratio A ratio is the comparison of two numbers or quantities. A ratio may be expressed in three ways: as a fraction, with a colon, or with the word “to.” For example, a gear ratio of 5:7 can be expressed as any of the following: ### Aviation Applications Ratios have widespread application in the field of aviation. Example: Compression ratio on a reciprocating engine is the ratio of the volume of a cylinder with the piston at the bottom of its stroke to the volume of the cylinder with the piston at the top of its stroke. For example, a typical compression ratio might be 10:1 (or 10 to 1). Aspect ratio is the ratio of the length (or span) of an airfoil to Figure labels: 5⁄16 inch socket (20⁄64 reduced).; 5⁄7 or 5:7 or 5 to 7 [General p. 3-8] its width (or chord). A typical aspect ratio for a commercial airliner might be 7:1 (or 7 to 1). Air-fuel ratio is the ratio of the weight of the air to the weight of fuel in the mixture being fed into the cylinders of a reciprocating engine. For example, a typical air-fuel ratio might be 14.3:1 (or 14.3 to 1). Glide ratio is the ratio of the forward distance traveled to the vertical distance descended when an aircraft is operating without power. For example, if an aircraft descends 1,000 feet while it travels through the air for two linear miles (10,560 feet), it has a glide ratio of 10,560:1,000 which can be reduced to 10.56: 1 (or 10.56 to 1). Gear ratio is the number of teeth each gear represents when two gears are used in an aircraft component. In Figure 3-7, the pinion gear has 8 teeth and a spur gear has 28 teeth. The gear ratio is 8:28. Using 7 as the LCD, 8:28 becomes 2:7. Speed ratio is when two gears are used in an aircraft component; the rotational speed of each gear is represented as a speed ratio. As the number of teeth in a gear decreases, the rotational speed of that gear increases, and vice-versa. Therefore, the speed ratio of two gears is the inverse (or opposite) of the gear ratio. If two gears have a gear ratio of 2:9, then their speed ratio is 9:2. Example: A pinion gear with 10 teeth is driving a spur gear with 40 teeth. The spur gear is rotating at 160 rpm. Calculate the speed of the pinion gear. Teeth in Pinion Gear = Speed of Spur Gear Teeth in Spur Gear Speed of Pinion Gear 10 teeth = 160 rpm 40 teeth SP (speed of pinion gear) To solve for SP, multiply 40 × 160, then divide by 10. The speed of the pinion gear is 640 rpm. Example: If the cruising speed of an airplane is 200 knots and its maximum speed is 250 knots, what is the ratio of cruising speed to maximum speed? First, express the cruising speed as the numerator of a fraction whose denominator is the maximum speed. Ratio = 200 250 Next, reduce the resulting fraction to its simplest form. Ratio = 200250= 4 5 Therefore, the ratio of cruising speed to maximum speed is 4:5. Another common use of ratios is to convert any given ratio to an equivalent ratio with a denominator of 1. Example: Express the ratio 9:5 as a ratio with a denominator of 1. R = 9 = ? Since 9 ÷ 5 = 1.8, then 9 = 1.8 5 1 5 1 Therefore, 9:5 is the same ratio as 1.8:1. In other words, 9 to 5 is the same ratio as 1.8 to 1. ## Proportion A proportion is a statement of equality between two or more ratios. For example, 3 = 6 or 3:4 = 6:8 4 8 This proportion is read as, “3 is to 4 as 6 is to 8.” ### Extremes and Means The first and last terms of the proportion (the 3 and 8 in this example) are called the extremes. The second and third terms (the 4 and 6 in this example) are called the means. In any proportion, the product of the extremes is equal to the product of the means. In the proportion 2:3 = 4:6, the product of the extremes, 2 × 6, is 12; the product of the means, 3 × 4, is also 12. An inspection of any proportion shows this to be true. ### Solving Proportions Normally when solving a proportion, three quantities are known, and the fourth is unknown. To solve for the unknown, multiply the two numbers along the diagonal and then divide by the third number. Example: Solve for X in the proportion given below. 65 = X 80 100 First, multiply 65 × 100: 65 × 100 = 6500 Next, divide by 80: 6500 ÷ 80 = 81.25 Therefore, X = 81.25. Example: An airplane flying 300 miles used 24 gallons of gasoline. How many gallons will it need to travel 750 miles? The ratio here is: “miles to gallons;” therefore, the proportion is set up as: 300 = 750 Miles 24 Gallons G [General p. 3-9] *Figure 3-6. Fractions, decimals, and millimeters.* Figure/table content: Fraction | Decimal | MM | Fraction | Decimal | MM | Fraction | Decimal | MM 1/64 | 0.015 | 0.396 | 1 1/64 | 1.015 | 25.796 | 2 1/64 | 2.015 | 51.196 1/32 | 0.031 | 0.793 | 1 1/32 | 1.031 | 26.193 | 2 1/32 | 2.031 | 51.593 3/64 | 0.046 | 1.190 | 1 3/64 | 1.046 | 26.590 | 2 3/64 | 2.046 | 51.990 1/16 | 0.062 | 1.587 | 1 1/16 | 1.062 | 26.987 | 2 1/16 | 2.062 | 52.387 5/64 | 0.078 | 1.984 | 1 5/64 | 1.078 | 27.384 | 2 5/64 | 2.078 | 52.784 3/32 | 0.093 | 2.381 | 1 3/32 | 1.093 | 27.781 | 2 3/32 | 2.093 | 53.181 7/64 | 0.109 | 2.778 | 1 7/64 | 1.109 | 28.178 | 2 7/64 | 2.109 | 53.578 0.125 | 3.175 | 1 1/8 | 1.125 | 28.575 | 2 1/8 | 2.125 | 53.975 9/64 | 0.140 | 3.571 | 1 9/64 | 1.140 | 28.971 | 2 9/64 | 2.140 | 54.371 5/32 | 0.156 | 3.968 | 1 5/32 | 1.156 | 29.368 | 2 5/32 | 2.156 | 54.768 11/64 | 0.171 | 4.365 | 1 11/64 | 1.171 | 29.765 | 2 11/64 | 2.171 | 55.165 3/16 | 0.187 | 4.762 | 1 3/16 | 1.187 | 30.162 | 2 3/16 | 2.187 | 55.562 13/64 | 0.203 | 5.159 | 1 13/64 | 1.203 | 30.559 | 2 13/64 | 2.203 | 55.959 7/32 | 0.218 | 5.556 | 1 7/32 | 1.218 | 30.956 | 2 7/32 | 2.218 | 56.356 15/64 | 0.234 | 5.953 | 1 15/64 | 1.234 | 31.353 | 2 15/64 | 2.234 | 56.753 0.25 | 6.35 | 1 1/4 | 1.25 | 31.75 | 2 1/4 | 2.25 | 57.15 17/64 | 0.265 | 6.746 | 1 17/64 | 1.265 | 32.146 | 2 17/64 | 2.265 | 57.546 9/32 | 0.281 | 7.143 | 1 9/32 | 1.281 | 32.543 | 2 9/32 | 2.281 | 57.943 19/64 | 0.296 | 7.540 | 1 19/64 | 1.296 | 32.940 | 2 19/64 | 2.296 | 58.340 5/16 | 0.312 | 7.937 | 1 5/16 | 1.312 | 33.337 | 2 5/16 | 2.312 | 58.737 21/64 | 0.328 | 8.334 | 1 21/64 | 1.328 | 33.734 | 2 21/64 | 2.328 | 59.134 11/32 | 0.343 | 8.731 | 1 11/32 | 1.343 | 34.131 | 2 11/32 | 2.343 | 59.531 23/64 | 0.359 | 9.128 | 1 23/64 | 1.359 | 34.528 | 2 23/64 | 2.359 | 59.928 0.375 | 9.525 | 1 3/8 | 1.375 | 34.925 | 2 3/8 | 2.375 | 60.325 25/64 | 0.390 | 9.921 | 1 25/64 | 1.390 | 35.321 | 2 25/64 | 2.390 | 60.721 13/32 | 0.406 | 10.318 | 1 13/32 | 1.406 | 35.718 | 2 13/32 | 2.406 | 61.118 27/64 | 0.421 | 10.715 | 1 27/64 | 1.421 | 36.115 | 2 27/64 | 2.421 | 61.515 7/16 | 0.437 | 11.112 | 1 7/16 | 1.437 | 36.512 | 2 7/16 | 2.437 | 61.912 29/64 | 0.453 | 11.509 | 1 29/64 | 1.453 | 36.909 | 2 29/64 | 2.453 | 62.309 15/32 | 0.468 | 11.906 | 1 15/32 | 1.468 | 37.306 | 2 15/32 | 2.468 | 62.706 31/64 | 0.484 | 12.303 | 1 31/64 | 1.484 | 37.703 | 2 31/64 | 2.484 | 63.103 12.7 | 1 1/2 | 38.1 | 2 1/2 | 63.5 33/64 | 0.515 | 13.096 | 1 33/64 | 1.515 | 38.496 | 2 33/64 | 2.515 | 63.896 17/32 | 0.531 | 13.493 | 1 17/32 | 1.531 | 38.893 | 2 17/32 | 2.531 | 64.293 35/64 | 0.546 | 13.890 | 1 35/64 | 1.546 | 39.290 | 2 35/64 | 2.546 | 64.690 39341 | 0.562 | 14.287 | 1 9/16 | 1.562 | 39.687 | 2 9/16 | 2.562 | 65.087 37/64 | 0.578 | 14.684 | 1 37/64 | 1.578 | 40.084 | 2 37/64 | 2.578 | 65.484 19/32 | 0.593 | 15.081 | 1 19/32 | 1.593 | 40.481 | 2 19/32 | 2.593 | 65.881 39/64 | 0.609 | 15.478 | 1 39/64 | 1.609 | 40.878 | 2 39/64 | 2.609 | 66.278 0.625 | 15.875 | 1 5/8 | 1.625 | 41.275 | 2 5/8 | 2.625 | 66.675 41/64 | 0.640 | 16.271 | 1 41/64 | 1.640 | 41.671 | 2 41/64 | 2.640 | 67.071 21/32 | 0.656 | 16.668 | 1 21/32 | 1.656 | 42.068 | 2 21/32 | 2.656 | 67.468 43/64 | 0.671 | 17.065 | 1 43/64 | 1.671 | 42.465 | 2 43/64 | 2.671 | 67.865 11/16 | 0.687 | 17.462 | 1 11/16 | 1.687 | 42.862 | 2 11/16 | 2.687 | 68.262 45/64 | 0.703 | 17.859 | 1 45/64 | 1.703 | 43.259 | 2 45/64 | 2.703 | 68.659 23/32 | 0.718 | 18.256 | 1 23/32 | 1.718 | 43.656 | 2 23/32 | 2.718 | 69.056 47/64 | 0.734 | 18.653 | 1 47/64 | 1.734 | 44.053 | 2 47/64 | 2.734 | 69.453 0.75 | 19.05 | 1 3/4 | 1.75 | 44.45 | 2 3/4 | 2.75 | 69.85 49/64 | 0.765 | 19.446 | 1 49/64 | 1.765 | 44.846 | 2 49/64 | 2.765 | 70.246 25/32 | 0.781 | 19.843 | 1 25/32 | 1.781 | 45.243 | 2 25/32 | 2.781 | 70.643 51/64 | 0.796 | 20.240 | 1 51/64 | 1.796 | 45.640 | 2 51/64 | 2.796 | 71.040 13/16 | 0.812 | 20.637 | 1 13/16 | 1.812 | 46.037 | 2 13/16 | 2.812 | 71.437 53/64 | 0.828 | 21.034 | 1 53/64 | 1.828 | 46.434 | 2 53/64 | 2.828 | 71.834 27/32 | 0.843 | 21.431 | 1 27/32 | 1.843 | 46.831 | 2 27/32 | 2.843 | 72.231 55/64 | 0.859 | 21.828 | 1 55/64 | 1.859 | 47.228 | 2 55/64 | 2.859 | 72.628 0.875 | 22.225 | 1 7/8 | 1.875 | 47.625 | 2 7/8 | 2.875 | 73.025 57/64 | 0.890 | 22.621 | 1 57/64 | 1.890 | 48.021 | 2 57/64 | 2.890 | 73.421 29/32 | 0.906 | 23.018 | 1 29/32 | 1.906 | 48.418 | 2 29/32 | 2.906 | 73.818 59/64 | 0.921 | 23.415 | 1 59/64 | 1.921 | 48.815 | 2 59/64 | 2.921 | 74.215 15/16 | 0.937 | 23.812 | 1 15/16 | 1.937 | 49.212 | 2 15/16 | 2.937 | 74.612 61/64 | 0.953 | 24.209 | 1 61/64 | 1.953 | 49.609 | 2 61/64 | 2.953 | 75.009 31/32 | 0.968 | 24.606 | 1 31/32 | 1.968 | 50.006 | 2 31/32 | 2.968 | 75.406 63/64 | 0.984 | 25.003 | 1 63/64 | 1.984 | 50.403 | 2 63/64 | 2.984 | 75.803 25.4 | 50.8 | 76.2 [General p. 3-10] Solve for G: (750 × 24) ÷ 300 = 60 Therefore, to fly 750 miles, 60 gallons of gasoline is required. ## Percentage Percentage means “parts out of one hundred.” The percentage sign is “%.” Ninety percent is expressed as 90% (= 90 parts out of 100). The decimal 0.90 equals 90⁄100, or 90 out of 100, or 90%. ### Expressing a Decimal Number as a Percentage To express a decimal number in percent, move the decimal point two places to the right (adding zeroes if necessary) and then affix the percent symbol. Example: Express the following decimal numbers as a percent: 0.90 = 90% 0.5 = 50% 1.25 = 125% 0.335 = 33.5% ### Expressing a Percentage as a Decimal Number Sometimes it may be necessary to express a percentage as a decimal number. To express a percentage as a decimal number, move the decimal point two places to the left and drop the % symbol. For example: Express the following percentages as decimal numbers: 90% = 0.90 50% = 0.50 5% = 0.05 150% = 1.5 ### Expressing a Fraction as a Percentage To express a fraction as a percentage, first change the fraction to a decimal number (by dividing the numerator by the denominator), and then convert the decimal number to a percentage by multiplying by 100 as shown earlier. Example: Express the fraction 5⁄8 as a percentage. 5 = 5 ÷ 8 = 0.625 = 62.5% 8 ### Finding a Percentage of a Given Number This is the most common type of percentage calculation. Here are two methods to solve percentage problems: using algebra or using proportions. Each method is shown next to find a percent of a given number. Example: In a shipment of 80 wingtip lights, 15% of the lights were defective. How many of the lights were defective? ### Algebraic Method: 15% of 80 lights = N (number of defective lights) 0.15 × 80 = N 12 = N Therefore, 12 defective lights were in the shipment. ### Proportion Method: N = 15 80 100 To solve for N: N × 100 = 80 × 15 N × 100 = 1,200 N = 1,200 ÷ 100 N = 12 or N = (80 × 15) ÷ 100 N = 12 ### Finding What Percentage One Number is of Another Example: A small engine rated at 12 horsepower is found to be delivering only 10.75 horsepower. What is the motor efficiency expressed as a percent? ### Algebraic Method: N% of 12 rated horsepower = 10.75 actual horsepower N% × 12 = 10.75 N% = 10.75 ÷ 12 N% = 0.8958 N = 89.58 Therefore, the motor efficiency is 89.58%. ### Proportion Method: 10.75 = N 12 100 *Figure 3-7. Gear ratio.* [General p. 3-11] To solve for N: N × 12 = 10.75 × 100 N × 12 = 1,075 N = 1,075 ÷ 12 N = 89.58 or N = (1,075 × 100) ÷ 12 N = 89.58 Therefore, the motor efficiency is 89.58%. ### Finding a Number When a Percentage of it is Known Example: Eighty ohms represents 52% of a microphone’s total resistance. Find the total resistance of this microphone. ### Algebraic Method: 52% of N = 80 ohms 52% × N = 80 N = 80 ÷ 0.52 N = 153.846 The total resistance of the microphone is 153.846 ohms. ### Proportion Method: = 52 80 100 N To solve for N: N × 52 = 80 × 100 N × 52 = 8,000 N = 8,000 ÷ 52 N = 153.846 ohms or N = (80 × 100) ÷ 52 N = 153.846 ohms ## Positive & Negative Numbers (Signed Numbers) Positive numbers are numbers that are greater than zero. Negative numbers are numbers less than zero. [Figure 3-8] Signed numbers are also called integers. ### Addition of Positive & Negative Numbers The sum (addition) of two positive numbers is positive. The sum (addition) of two negative numbers is negative. The sum of a positive and a negative number can be positive or negative, depending on the values of the numbers. A good way to visualize a negative number is to think in terms of debt. If you are in debt by $100 (or, −100) and you add $45 to your account, you are now only $55 in debt (or −55). Therefore: −100 + 45 = −55. Example: The weight of an aircraft is 2,000 pounds. A radio rack weighing 3 pounds and a transceiver weighing 10 pounds are removed from the aircraft. What is the new weight? For weight and balance purposes, all weight removed from an aircraft is given a minus sign, and all weight added is given a plus sign. 2,000 + −3 + −10 = 2,000 + −13 = 1,987 Therefore, the new weight is 1,987 pounds. ### Subtraction of Positive & Negative Numbers To subtract positive and negative numbers, first change the “–” (subtraction symbol) to a “+” (addition symbol), and change the sign of the second number to its opposite (that is, change a positive number to a negative number or vice versa). Finally, add the two numbers together. Example: The daytime temperature in the city of Denver was 6° below zero (−6°). An airplane is cruising at 15,000 feet above Denver. The temperature at 15,000 feet is 20° colder than in the city of Denver. What is the temperature at 15,000 feet? Subtract 20 from −6: −6 – 20 = −6 + (−20) = −26 The temperature is −26°, or 26° below zero at 15,000 feet above the city. ### Multiplication of Positive & Negative Numbers The product of two positive numbers is always positive. The product of two negative numbers is always positive. The product of a positive and a negative number is always negative. Examples: 3 × 6 = 18 −3 × 6 = −18 −3 × −6 = 18 3 × −6 = −18 ### Division of Positive & Negative Numbers The quotient of two positive numbers is always positive. The quotient of two negative numbers is always positive. The quotient of a positive and negative number is always negative. Examples: 6 ÷ 3 = 2 −6 ÷ 3 = −2 −6 ÷ −3 = 2 6 ÷ −3 = −2 ## Powers The power (or exponent) of a number is a shorthand method of indicating how many times a number, called the base, is multiplied by itself. For example, 34 is read as “3 to the power of 4.” That is, 3 multiplied by itself 4 times. The 3 is the base and 4 is the power. Examples: 23 = 2 × 2 × 2 = 8 [General p. 3-12] Read “two to the third power equals 8.” 105 = 10 × 10 × 10 × 10 × 10 = 100,000 Read “ten to the fifth power equals 100,000.” ### Special Powers Squared When a number has a power of 2, it is commonly referred to as “squared.” For example, 72 is read as “seven squared” or “seven to the second power.” To remember this, think about how a square has two dimensions: length and width. ## Cubed When a number has a power of 3, it is commonly referred to as “cubed.” For example, 73 is read as “seven cubed” or “seven to the third power.” To remember this, think about how a cube has three dimensions: length, width, and depth. ## Power of Zero Any non-zero number raised to the zero power always equals 1. Example: 70 = 1 1810 = 1 (–24)0 = 1 ### Negative Powers A number with a negative power equals its reciprocal with the same power made positive. Example: The number 2-3 is read as “2 to the negative 3rd power,” and is calculated by: 2-3 = 123= 1 = 1 2 × 2 × 2 8 When using a calculator to raise a negative number to a power, always place parentheses around the negative number (before raising it to a power) so that the entire number gets raised to the power. ### Law of Exponents When multiplying numbers with powers, the powers can be added as long as the bases are the same. Example: 32 × 34 = (3 × 3) × (3 × 3 × 3 × 3) = 3 × 3 × 3 × 3 × 3 × 3 = 36 or 32 × 34 = 3(2+4) = 36 When dividing numbers with powers, the powers can be subtracted as long as the bases are the same. Example: 104 ÷ 102 =10 × 10 × 10 × 10 =10 × 10 × 10 × 10 =10 × 10 =102 10 × 10 10 × 10 or 104 ÷ 102 = 10(4 – 2) = 102 ### Powers of Ten Because we use the decimal system of numbers, powers of ten are frequently seen in everyday applications. For example, scientific notation uses powers of ten. Also, many aircraft drawings are scaled to powers of ten. Figure 3-9 gives more information on the powers of ten and their values. ### Roots A root is a number that when multiplied by itself a specified number of times produces a given number. The two most common roots are the square root and the cube root. For more examples of roots, see Figure 3-10. ### Square Roots The square root of 25, written as 25, equals 5. That is, when the number 5 is squared (multiplied by itself), it produces the number 25. The symbol is called a radical sign. Finding the square root of a number is the most common application of roots. The collections of numbers whose square roots are whole numbers are called perfect squares. The first ten perfect squares are: 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. The square root of each of these numbers is 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10, respectively. For example, 36 = 6 and 81 = 9 To find the square root of a number that is not a perfect square, use either a calculator or the estimation method. A longhand method does exist for finding square roots, but with the advent of calculators and because of its lengthy explanation, it is no longer included in this handbook. The estimation method uses the knowledge of perfect squares to approximate the square root of a number. Example: Find the square root of 31. Since 31 falls between the two perfect roots 25 and 36, we know that must be between 25 and 36. Therefore, 31 must be greater than 5 and less than 6 because 25 = 5 and 36 = 6. If you estimate the square root of 31 at 5.5, you are close to the correct answer. The square root of 31 is actually 5.568. *Figure 3-8. A scale of signed numbers.* [General p. 3-13] ### Cube Roots The cube root of 125, written as 3125, equals 5. That is, when the number 5 is cubed (5 multiplied by itself then multiplying the product (25) by 5 again), it produces the number 125. It is common to confuse the “cube” of a number with the “cube root” of a number. For clarification, the cube of 27 = 273 = 27 × 27 × 27 = 19,683. However, the cube root of 27 = 327 = 3. ### Fractional Powers Another way to write a root is to use a fraction as the power (or exponent) instead of the radical sign. The square root of a number is written with a 1⁄2 as the exponent instead of a radical sign. The cube root of a number is written with an exponent of 1⁄3 and the fourth root with an exponent of 1⁄4 and so on. Example: 31 = 31 ## Functions of Numbers Chart The Functions of Numbers chart found in Figure 3-10 is included in this chapter for convenience in making computations. Each column in the chart is listed below, with new concepts explained. • Number (N) • N squared (N2) N cubed (N3) • • Square root of N (N) Cube root of N (3N) • • Circumference of a circle with diameter = N. Circumference is the linear measurement of the distance around a circle. The circumference is calculated by multiplying the diameter of the circle by 3.1416 (3.1416 is the number referred to as pi, which has the symbol π). If the diameter of a circle is 10 inches, then the circumference would be: 10 × 3.1416 = 31.4160. • Area of a circle with diameter = N. Area of a circle is the number of square units of measurement contained in the circle with a diameter of N. The area of a circle equals π multiplied by the radius squared. This is calculated by the formula: A = π × r2. Remember that the radius is equal to one-half of the diameter. Example: A flight deck instrument gauge has a round face that is 3 inches in diameter. What is the area of the face of the gauge? From Figure 3-10 for N = 3, the answer is 7.0686 square inches. This is calculated by: If the diameter of the gauge is 3 inches, then the radius = D⁄2 = 3⁄2 = 1.5 inches. Area = π × r2 = 3.1416 × 1.52 = 3.1416 × 2.25 = 7.0686 square inches. ## Scientific Notation Scientific notation is used as a type of shorthand to express very large or very small numbers. It is a way to write numbers so that they do not take up as much space on the page. The format of a number written in scientific notation has two parts. The first part is a number greater than or equal to 1 and less than 10 (for example, 2.35). The second part is a power of 10 (for example, 106). The number 2,350,000 is expressed in scientific notation as 2.35 × 106. It is important that the decimal point is always placed to the right of the first digit. Notice that very large numbers always have a positive power of 10 and very small numbers always have a negative power of 10. Example: The velocity of the speed of light is over 186,000 miles per second (mps). This can be expressed as 1.86 × 105 mps in scientific notation. The mass of an electron is approximately 0.000,000,000,000,000,000,000,000,000,911 grams. This can be expressed in scientific notation as 9.11 × 10-28 grams. ### Converting Numbers from Standard Notation to Scientific Notation Example: Convert 1,244,000,000,000 to scientific notation as follows. First, note that the decimal point is to the right of the last zero. (Even though it is not usually written, it is assumed to be there.) *Figure 3-9. Powers of ten.* Figure/table content: Expansion | Value 10 x 10 x 10 x 10 x 10 x 10 | 1,000,000 10 x 10 x 10 x 10 x 10 | 100,000 10 x 10 x 10 x 10 | 10,000 10 x 10 x 10 | 1,000 10-1 | 1/10 | 1/10=0.1 10-2 | 1/(10 x 10) | 1/100=0.01 1⁄23125 = 1251⁄3416 = 16 | 10-3 | 1/(10 x 10 x 10) | 1/1,000=0.001 10-4 | 1/(10 x 10 x 10 x 10) | 1/10,000=0.0001 10-5 | 1/(10 x 10 x 10 x 10 x 10) | 1/100,000=0.00001 10-6 | 1/(10 x 10 x 10 x 10 x 10 x 10) | 1/1,000,000=0.000001 Figure labels: Powers; of Ten; Positive; Exponents; 10 x 10; Negative [General p. 3-14] *Figure 3-10. Functions of numbers.* Figure/table content: Number | Square | Cube | Square Root | Cube Root | Circumference | Area Circumference | Area of a Square Root | Cube Root Number (N) | N Squared (N2) | N Cubed (N3) | of a circle with | circle with of N (√N) | of N (√N)3 diameter = N | diameter = N 1.000 | 1.000 | 3.142 | 0.785 1.414 | 1.260 | 6.283 | 3.142 1.732 | 1.442 | 9.425 | 7.069 2.000 | 1.587 | 12.566 | 12.566 2.236 | 1.710 | 15.708 | 19.635 2.449 | 1.817 | 18.850 | 28.274 2.646 | 1.913 | 21.991 | 38.484 2.828 | 2.000 | 25.133 | 50.265 3.000 | 2.080 | 28.274 | 63.617 1,000 | 3.162 | 2.154 | 31.416 | 78.540 1,331 | 3.317 | 2.224 | 34.558 | 95.033 1,728 | 3.464 | 2.289 | 37.699 | 113.01 2,197 | 3.606 | 2.351 | 40.841 | 132.73 2,744 | 3.742 | 2.410 | 43.982 | 153.94 3,375 | 3.873 | 2.466 | 47.124 | 176.71 4,096 | 4.000 | 2.520 | 50.265 | 201.06 4,913 | 4.123 | 2.571 | 53.407 | 226.98 5,832 | 4.243 | 2.621 | 56.549 | 254.47 6,859 | 4.359 | 2.668 | 59.690 | 283.53 8,000 | 4.472 | 2.714 | 62.832 | 314.16 9,261 | 4.583 | 2.759 | 65.973 | 346.36 10,648 | 4.690 | 2.802 | 69.115 | 380.13 12,167 | 4.796 | 2.844 | 72.257 | 415.48 13,824 | 4.899 | 2.885 | 75.398 | 452.39 15,625 | 5.000 | 2.924 | 78.540 | 490.87 17,576 | 5.099 | 2.963 | 81.681 | 530.93 19,683 | 5.196 | 3.000 | 84.823 | 572.55 21,952 | 5.292 | 3.037 | 87.965 | 615.75 24,389 | 5.385 | 3.072 | 91.106 | 660.52 27,000 | 5.477 | 3.107 | 94.248 | 706.86 29,791 | 5.568 | 3.141 | 97.389 | 754.77 1,024 | 32,768 | 5.657 | 3.175 | 100.531 | 804.25 1,089 | 35,937 | 5.745 | 3.208 | 103.672 | 855.30 1,156 | 39,304 | 5.831 | 3.240 | 106.814 | 907.92 1,225 | 42,875 | 5.916 | 3.271 | 109.956 | 962.11 1,296 | 46,656 | 6.000 | 3.302 | 113.097 | 1017.88 1,369 | 50,653 | 6.083 | 3.332 | 116.239 | 1075.21 1,444 | 54,872 | 6.164 | 3.362 | 119.380 | 1134.11 1,521 | 59,319 | 6.245 | 3.391 | 122.522 | 1194.59 1,600 | 64,000 | 6.325 | 3.420 | 125.664 | 1256.64 1,681 | 68,921 | 6.403 | 3.448 | 128.805 | 1320.25 1,764 | 74,088 | 6.481 | 3.476 | 131.947 | 1385.44 1,849 | 79,507 | 6.557 | 3.503 | 135.088 | 1452.20 1,936 | 85,184 | 6.633 | 3.530 | 138.230 | 1520.53 2,025 | 91,125 | 6.708 | 3.557 | 141.372 | 1590.43 2,116 | 97,336 | 6.782 | 3.583 | 144.513 | 1661.90 2,209 | 103,823 | 6.856 | 3.609 | 147.655 | 1734.94 2,304 | 110,592 | 6.928 | 3.634 | 150.796 | 1809.56 2,401 | 117,649 | 7.000 | 3.659 | 153.938 | 1885.74 2,500 | 125,000 | 7.071 | 3.684 | 157.080 | 1963.49 [General p. 3-15] *Figure 3-10. Functions of numbers (continued).* Figure/table content: Number | Square | Cube | Square Root | Cube Root | Circumference | Area Circumference | Area of a Square Root | Cube Root Number (N) | N Squared (N2) | N Cubed (N3) | of a circle with | circle with of N (√N) | of N (√N)3 diameter = N | diameter = N 2,601 | 132,651 | 7.141 | 3.708 | 160.221 | 2042.82 2,704 | 140,608 | 7.211 | 3.733 | 163.363 | 2123.71 2,809 | 148,877 | 7.280 | 3.756 | 166.504 | 2206.18 2,916 | 157,464 | 7.348 | 3.780 | 169.646 | 2290.22 3,025 | 166,375 | 7.416 | 3.803 | 172.787 | 2375.83 3,136 | 175,616 | 7.483 | 3.826 | 175.929 | 2463.01 3,249 | 185,193 | 7.550 | 3.849 | 179.071 | 2551.76 3,364 | 195,112 | 7.616 | 3.871 | 182.212 | 2642.08 3,481 | 205,379 | 7.681 | 3.893 | 185.354 | 2733.97 3,600 | 216,000 | 7.746 | 3.915 | 188.495 | 2827.43 3,721 | 226,981 | 7.810 | 3.937 | 191.637 | 2922.46 3,844 | 238,328 | 7.874 | 3.958 | 194.779 | 3109.07 3,969 | 250,047 | 7.937 | 3.979 | 197.920 | 3117.24 4,096 | 262,144 | 8.000 | 4.000 | 201.062 | 3216.99 4,225 | 274,625 | 8.062 | 4.021 | 204.203 | 3318.30 4,356 | 287,496 | 8.124 | 4.041 | 207.345 | 3421.19 4,489 | 300,763 | 8.185 | 4.062 | 210.487 | 3525.65 4,624 | 314,432 | 8.246 | 4.082 | 213.628 | 3631.68 4,761 | 328,509 | 8.307 | 4.102 | 216.770 | 3739.28 4,900 | 343,000 | 8.367 | 4.121 | 219.911 | 3848.45 5,041 | 357,911 | 8.426 | 4.141 | 223.053 | 3959.19 5,184 | 373,248 | 8.485 | 4.160 | 226.194 | 4071.50 5,329 | 389,017 | 8.544 | 4.179 | 229.336 | 4185.38 5,476 | 405,224 | 8.602 | 4.198 | 232.478 | 4300.84 5,625 | 421,875 | 8.660 | 4.217 | 235.619 | 4417.86 5,776 | 438,976 | 8.718 | 4.236 | 238.761 | 4536.46 5,929 | 456,533 | 8.775 | 4.254 | 241.902 | 4656.62 6,084 | 474,552 | 8.832 | 4.273 | 245.044 | 4778.36 6,241 | 493,039 | 8.888 | 4.291 | 248.186 | 4901.67 6,400 | 512,000 | 8.944 | 4.309 | 251.327 | 5026.54 6,561 | 531,441 | 9.000 | 4.327 | 254.469 | 5152.99 6,724 | 551,368 | 9.055 | 4.344 | 257.610 | 5281.01 6,889 | 571,787 | 9.110 | 4.362 | 260.752 | 5410.60 7,056 | 592,704 | 9.165 | 4.380 | 263.894 | 5541.76 7,225 | 614,125 | 9.220 | 4.397 | 267.035 | 5674.50 7,396 | 636,056 | 9.274 | 4.414 | 270.177 | 5808.80 7,569 | 658,503 | 9.327 | 4.431 | 273.318 | 5944.67 7,744 | 681,472 | 9.381 | 4.448 | 276.460 | 6082.12 7,921 | 704,969 | 9.434 | 4.465 | 279.602 | 6221.13 8,100 | 729,000 | 9.487 | 4.481 | 282.743 | 6361.72 8,281 | 753,571 | 9.539 | 4.498 | 285.885 | 6503.88 8,464 | 778,688 | 9.592 | 4.514 | 289.026 | 6647.60 8,649 | 804,357 | 9.644 | 4.531 | 292.168 | 6792.90 8,836 | 830,584 | 9.695 | 4.547 | 295.309 | 6939.77 9,025 | 857,375 | 9.747 | 4.563 | 298.451 | 7088.21 9,216 | 884,736 | 9.798 | 4.579 | 301.593 | 7238.22 9,409 | 912,673 | 9.849 | 4.595 | 304.734 | 7389.81 9,604 | 941,192 | 9.900 | 4.610 | 307.876 | 7542.96 9,801 | 970,299 | 9.950 | 4.626 | 311.017 | 7697.68 10,000 | 1,000,000 | 10.000 | 4.642 | 314.159 | 7853.98 [General p. 3-16] 1,244,000,000,000 = 1,244,000,000,000.0 To change to the format of scientific notation, the decimal point must be moved to the position between the first and second digits. In this case, it is between the 1 and the 2. Since the decimal point must be moved 12 places to the left to get there, the power of 10 is 12. Remember that large numbers always have a positive exponent. Therefore, 1,244,000,000,000 = 1.244 × 1012 when written in scientific notation. Example: Convert 0.000000457 from standard notation to scientific notation. To change to the format of scientific notation, the decimal point must be moved to the position between the first and second numbers, which in this case is between the 4 and the 5. Since the decimal point must be moved 7 places to the right to get there, the power of 10 is −7. Remember that small numbers (those less than one) have a negative exponent. Therefore, 0.000000457 = 4.57 × 10-7 when written in scientific notation. ### Converting Numbers from Scientific Notation to Standard Notation Example: Convert 3.68 × 107 from scientific notation to standard notation, as follows. To convert from scientific notation to standard notation, move the decimal place 7 places to the right. 3.68 × 107 = 36,800,000. Another way to think about the conversion is 3.68 × 107 = 3.68 × 10,000,000 = 36,800,000. Example: Convert 7.1543 × 10-10 from scientific notation to standard notation. Move the decimal place 10 places to the left: 7.1543 × 10-10 =.00000000071543. Another way to think about the conversion is 7.1543 × 10-10 = 7.1543 × 0.0000000001 = 0.00000000071543 When converting, remember that large numbers always have positive powers of ten and small numbers always have negative powers of ten. Refer to Figure 3-11 to determine which direction to move the decimal point. ### Addition, Subtraction, Multiplication, and Division of Scientific Numbers To add, subtract, multiply, or divide numbers in scientific notation, change the scientific notation number back to standard notation. Then add, subtract, multiply or divide the standard notation numbers. After the computation, change the final standard notation number back to scientific notation. ## Algebra Algebra is the branch of mathematics that uses letters or symbols to represent variables in formulas and equations. For example, in the equation d = v × t, where distance = velocity × time, the variables are: d, v, and t. ### Equations Algebraic equations are frequently used in aviation to show the relationship between two or more variables. Equations normally have an equals sign (=) in the expression. Example: The formula A = π × r2 shows the relationship between the area of a circle (A) and the length of the radius (r)of the circle. The area of a circle is equal to π (3.1416) times the radius squared. The larger the radius, the larger the area of the circle. ### Algebraic Rules When solving for a variable in an equation, you can add, subtract, multiply, or divide the terms in the equation (you do the same to both sides of the equals sign) to get the variable onto one side of the equals sign. Examples: Solve the following equations for the value N. 3N = 21 To solve for N, divide both sides by 3. 3N ÷ 3 = 21 ÷ 3 N = 7 N + 17 = 59 To solve for N, subtract 17 from both sides. N + 17 – 17 = 59 – 17 N = 42 N – 22 = 100 To solve for N, add 22 to both sides. N – 22 + 22 = 100 + 22 N = 122 N = 50 5 To solve for N, multiply both sides by 5. N × 5 = 50 × 5 N = 250 ### Solving for a Variable Another application of algebra is to solve an equation for a given variable. Example: Using the formula given in Figure 3-12, find the total capacitance (CT) of the series circuit containing three capacitors with C1 = 0.1 microfarad C2 = 0.015 microfarad C3 = 0.05 microfarad First, substitute the given values into the formula: [General p. 3-17] 1 1 1 CT = = = 1 +1 +1 1 0.015 +11 10 + 66.66 + 20 0.1 + 0.05 C1 C2 C3 Therefore, CT = 1⁄96.66 = 0.01034 microfarad. The microfarad (10-6 farad) is a unit of measurement of capacitance. This is discussed in greater length in Chapter 12, Electricity. ### Use of Parentheses In algebraic equations, parentheses are used to group numbers or symbols together. The use of parentheses helps us to identify the order in which we should apply mathematical operations. The operations inside the parentheses are always performed first in algebraic equations. Example: Solve the algebraic equation X = (4 + 3)2. First, perform the operation inside the parentheses, which is, 4 + 3 = 7. Then complete the exponent calculation X = (7)2 = 7 × 7 = 49. When using more complex equations, which may combine several terms and use multiple operations, grouping the terms together helps organize the equation. Parentheses, ( ), are most commonly used in grouping, but you may also see brackets, [ ]. When a term or expression is inside one of these grouping symbols, it means that any operation indicated to be done on the group is done to the entire term or expression. Example: Solve the equation N = 2 × [(9 ÷ 3) + (4 + 3)2]. Start with the operations inside the parentheses ( ), then perform the operations inside the brackets [ ]. N = 2 × [(9 ÷ 3) + (4 + 3)2] N = 2 × [3 + (7)2] First, complete the operations inside the parentheses ( ). N = 2 × [3 + 49] N = 2 × [52] Second, complete the operations inside the brackets [ ]. N = 104 ### Order of Operation In algebra, rules have been set for the order in which operations are evaluated. These same universally accepted rules are also used when programming algebraic equations in calculators. When solving the following equation, the order of operation is given below: N = (62 – 54)2 + 62 – 4 + 3 × [8 + (10 ÷ 2)] + 25 + (42 × 2) ÷ 4 + 3⁄4 1. Parentheses. First you must do everything in parentheses, ( ), starting from the innermost parentheses. If the expression has a set of brackets, [ ], treat these exactly like parentheses. If you are working with a fraction, treat the top as if it was in parentheses and the denominator as if it were in parentheses, even if there is none shown. From the equation above, completing the calculation in parentheses gives the following: N = (8)2 + 62 – 4 + 3 × [8 + (5)] + 25 + (84) ÷ 4 + 3⁄4, then N = (8)2 + 62 – 4 + 3 × [13] + 25 + 84 ÷ 4 + 3⁄4 2. Exponents. Next, clear any exponents. Treat any roots (square roots, cube roots, and so forth) as exponents. Completing the exponents and roots in the equation gives the following: N = 64 + 36 – 4 + 3 × 13 + 5 + 84 ÷ 4 + 3⁄4 3. Multiplication and Division. Evaluate all of the multiplications and divisions from left to right. Multiply and divide from left to right in one step. A common error is to use two steps for this (that is, to clear all of the multiplication signs and then clear all of the division signs), but that is not the correct method. Treat fractions as division. Completing the multiplication and division in the equation gives the following: N = 64 + 36 – 4 + 39 + 5 + 21 + 3⁄4 4. Addition and Subtraction. Evaluate the additions and subtractions from left to right. Like above, addition and subtraction are computed left to right in one step. Completing the addition and subtraction in the equation gives the following: X = 161 3⁄4 A commonly used acronym, PEMDAS, is used for remembering the order of operation in algebra. PEMDAS is an acronym for parentheses, exponents, multiplication, *Figure 3-11. Converting between scientific and standard notation.* *Figure 3-12. Total capacitance in a series circuit.* Figure/table content: Large Numbers | Small Numbers Conversion | with Positive | with Negative Powers of 10 | Powers of 10 Move decimal | Move decimal place to the left | place to the right From scientific | CT=1 Move decimal | Move decimal place to the right | place to the left | C1 | C2 | C3 Figure labels: From standard; notation to scientific; notation; notation to standard [General p. 3-18] division, addition, and subtraction. To remember it, many use the sentence, “Please Excuse My Dear Aunt Sally.” Always remember, however, to multiply/divide or add/subtract in one sweep from left to right, not separately. ### Order of Operation for Algebraic Equations 1. Parentheses 2. Exponents 3. Multiplication 4. Division 5. Addition 6. Subtraction ## Computing Area of Two-Dimensional Solids Area is a measurement of the amount of surface of an object. Area is usually expressed in such units as square inches or square centimeters for small surfaces or in square feet or square meters for larger surfaces. Figure 3-13 summarizes the formulas for computing the area of two-dimensional solids. ### Rectangle A rectangle is a four-sided figure with opposite sides of equal length and parallel to each other. [Figure 3-14] All of the angles are right angles. A right angle is a 90° angle. The rectangle is a very familiar shape in mechanics. The formula for the area of a rectangle is: area = length × width = l × w Example: An aircraft floor panel is in the form of a rectangle having a length of 24 inches and a width of 12 inches. What is the area of the panel expressed in square inches? First, determine the known values and substitute them in the formula. a = l × w = 24 inches × 12 inches = 288 square inches ### Square A square is a four-sided figure with all sides of equal length and opposite sides are parallel to each other. [Figure 3-15] All angles are right angles. A right angle is a 90° angle. The formula for the area of a square is: area = length × width = l × w Since the length and the width of a square are the same value, the formula for the area of a square can also be written as: area = side × side = s2 Example: What is the area of a square access plate whose side measures 25 inches? First, determine the known value and substitute it in the formula. a = l × w = 25 inches × 25 inches = 625 square inches ### Triangle A triangle is a three-sided figure. The sum of the three angles in a triangle is always equal to 180°. Triangles are often classified by their sides. An equilateral triangle has 3 sides of equal length. An isosceles triangle has 2 sides of equal length. A scalene triangle has three sides of differing lengths. Triangles can also be classified by their angles. An acute triangle has all three angles less than 90°. A right triangle has one right angle (a 90° angle). An obtuse triangle has one angle greater than 90°. Each of these types of triangles is shown in Figure 3-16. The formula for the area of a triangle is area = 1⁄2 × (base × height) = 1⁄2 × (b × h) Example: Find the area of the obtuse triangle shown in Figure 3-17. First, substitute the known values in the area formula. a = 1⁄2 × (b × h) = 1⁄2 × (2'6" × 3'2") Next, convert all dimensions to inches: 2'6" = (2 × 12") + 6" = (24 + 6) = 30 inches 3'2" = (3 × 12") + 2" = (36 + 2) = 38 inches Now, solve the formula for the unknown value: a = 1⁄2 × (30 inches × 38 inches) = 570 square inches ### Parallelogram A parallelogram is a four-sided figure with two pairs of parallel sides. [Figure 3-18] Parallelograms do not necessarily have four right angles. The formula for the area of a parallelogram is: area = length × height = l × h ### Trapezoid A trapezoid is a four-sided figure with one pair of parallel sides. [Figure 3-19] The formula for the area of a trapezoid is: area = 1⁄2 (base1 + base2) × height [General p. 3-19] Example: What is the area of a trapezoid in Figure 3-19 whose bases are 14 inches and 10 inches, and whose height (or altitude) is 6 inches? First, substitute the known values in the formula. a = 1⁄2 (b1 + b2) × h = 1⁄2 (14 inches + 10 inches) × 6 inches a = 1⁄2 (24 inches) × 6 inches = 12 inches × 6 inches = 72 square inches ### Circle A circle is a closed, curved, plane figure. [Figure 3-20] Every point on the circle is an equal distance from the center of the circle. The diameter is the distance across the circle (through the center). The radius is the distance from the center to the edge of the circle. The diameter is always twice the length of the radius. The circumference, or distance around, a circle is equal to the diameter times π. circumference = c = d π The formula for the area of a circle is: area = π × radius2 = π × r2 Example: The bore, which is “inside diameter,” of a certain aircraft engine cylinder is 5 inches. Find the area of the cross section of the cylinder. First, substitute the known values in the formula: a = π × r2 The diameter is 5 inches, so the radius is 2.5 inches. (diameter = radius × 2) a = 3.1416 × (2.5 inches)2 = 3.1416 × 6.25 square inches = 19.635 square inches ### Ellipse An ellipse is a closed, curved, plane figure and is commonly called an oval. [Figure 3-21] In a radial engine, the articulating rods connect to the hub by pins, which travel in the pattern of an ellipse (i.e., an elliptical or orbital path). *Figure 3-13. Formulas to compute area.* *Figure 3-14. Rectangle.* *Figure 3-15. Square.* Figure/table content: Object | Area | Formula | Figure Rectangle | length × width | a = l × w | 3-14 Square | length × width or side × side | a = l × w or a = s2 | 3-15 ½ × (length × height) or | a = ½ (l × h) or Triangle | ½ × (base × height) or | a = ½ (b × h) or (base × height) ÷ 2 | a = (b × h) ÷ 2 Parallelogram | length × height | a = l × h | 3-18 Trapezoid | ½ (base1 + base2) × height | a = ½ (b1 + b2) × h | 3-19 Circle | π × radius2 | a = π × r2 | 3-20 Ellipse | π × semi-axis A × semi-axis B | a = π × a × b | 3-21 Wing area | span × mean chord | a = s × c | 3-22 l = 24 | s = 25 Figure labels: 3-16; 3-17; w = 12 [General p. 3-20] ### Wing Area To describe the shape of a wing [Figure 3-22], several terms are required. To calculate wing area, it is necessary to know the meaning of the terms “span” and “chord.” The wingspan, S, is the length of the wing from wingtip to wingtip. The chord is the average width of the wing from leading edge to trailing edge. If the wing is a tapered wing, the average width, known as the mean chord (C), must be known to find the area. The formula for calculating wing area is: area of a wing = span × mean chord Example: Find the area of a tapered wing whose span is 50 feet and whose mean chord is 6'8". First, substitute the known values in the formula. a = s × c = 50 feet × 6 feet 8 inches (Note: 8 inches = 8⁄12 feet = 0.67 feet) = 50 feet × 6.67 feet = 333.5 square feet ### Units of Area A square foot measures 1 foot by 1 foot. It also measures 12 inches by 12 inches. Therefore, one square foot also equals 144 square inches (that is, 12 × 12 = 144). To convert square feet to square inches, multiply by 144. To convert square inches to square feet, divide by 144. A square yard measures 1 yard by 1 yard. It also measures 3 feet by 3 feet. Therefore, one square yard also equals 9 square feet (that is, 3 × 3 = 9). To convert square yards to square feet, multiply by 9. To convert square feet to square yards, divide by 9. Refer to Figure 3-23, Applied Mathematics Formula Sheet, for a comparison of different units of area. ## Computing Volume of Three-Dimensional Solids Three-dimensional solids have length, width, and height. There are many three-dimensional solids, but the most common are rectangular solids, cubes, cylinders, spheres, and cones. Volume is the amount of space within a solid. Volume is expressed in cubic units. Cubic inches or cubic centimeters are used for small spaces and cubic feet or cubic meters for larger spaces. ### Rectangular Solid A rectangular solid is a three-dimensional solid with six rectangular-shaped sides. [Figure 3-24] The volume is the *Figure 3-16. Types of triangles.* *Figure 3-17. Obtuse triangle.* *Figure 3-18. Parallelogram.* *Figure 3-19. Trapezoid.* Figure/table content: Scalene | Isosceles | Equilateral Length of all sides | Length of two sides | Length of all sides are different | are equal | are equal Acute | Right | Obtuse Each angle is < 90° | One angle is = 90° | One angle is > 90° Figure labels: Triangles Based on Sides; Height; Triangles Based on Angles; Length; b2 = 10"; Height = 2 ft 6 in; Height = 6"; b1 = 14"; Base = 3 ft 2 in [General p. 3-21] number of cubic units within the rectangular solid. The formula for the volume of a rectangular solid is: volume = length × width × height = l × w × h In Figure 3-24, the rectangular solid is 3 feet by 2 feet by 2 feet. The volume of the solid in Figure 3-24 is = 3 ft × 2 ft × 2 ft = 12 cubic feet. Example: A rectangular baggage compartment measures 5 feet 6 inches in length, 3 feet 4 inches in width, and 2 feet 3 inches in height. How many cubic feet of baggage will it hold? First, substitute the known values into the formula. v = l × w × h = 5'6" × 3'4" × 2'3" = 5.5 ft × 3.33 ft × 2.25 ft = 41.25 cubic feet ### Cube A cube is a solid with six square sides. [Figure 3-25] A cube is just a special type of rectangular solid. It has the same formula for volume as does the rectangular solid, which is volume = length × width × height = L × W × H. Because all of the sides of a cube are equal, the volume formula for a cube can also be written as: volume = side × side × side = S3 Example: A large, cube-shaped carton contains a shipment of smaller boxes inside of it. Each of the smaller boxes is 1 ft × 1 ft × 1 ft. The measurement of the large carton is 3 ft × 3 ft × 3 ft. How many of the smaller boxes are in the large carton? First, substitute the known values into the formula. v = l × w × h = 3 ft × 3 ft × 3 ft = 27 cubic feet of volume in the large carton Since each of the smaller boxes has a volume of 1 cubic foot, the large carton holds 27 boxes. ### Cylinder A solid having the shape of a can, a length of pipe, or a barrel is called a cylinder. [Figure 3-26] The ends of a cylinder are identical circles. The formula for the volume of a cylinder is: volume = π × radius2 × height of the cylinder = π r2 × h One of the most important applications of the volume of a cylinder is finding the piston displacement of a cylinder in a reciprocating engine. Piston displacement is the total volume (in cubic inches, cubic centimeters, or liters) swept by all of the pistons of a reciprocating engine as they move in one revolution of the crankshaft. The formula for piston displacement is given as: Piston Displacement = π × (bore divided by 2)2 × stroke × (# cylinders) *Figure 3-20. Circle.* *Figure 3-21. Ellipse.* *Figure 3-22. Wing planform.* Figure labels: Diameter (d); a2 + b2; Circumference = c = 2π; π = 3.1416; a = Length of one of the semi-axes; b = Length of the other semi-axis; Area = a = π x a x b; a = Wing area, ft.2; c = Average chord, ft.; s = Span, ft. [General p. 3-22] The bore of an engine is the inside diameter of the cylinder. The stroke of the engine is the length the piston travels inside the cylinder. [Figure 3-27] Example: Find the piston displacement of one cylinder in a multi-cylinder aircraft engine. The engine has a cylinder bore of 5.5 inches and a stroke of 5.4 inches. First, substitute the known values in the formula. v = π × r2 × h = (3.1416) × (5.5 ÷ 2)2 × (5.4) v = 23.758 × 5.4 = 128.29 cubic inches The piston displacement of one cylinder is 128.29 cubic ## Conversion Factors inches. For an eight-cylinder engine, then the total engine displacement would be: Total displacement for 8 cylinders = 8 × 128.29 = 1026.32 cubic inches of displacement ### Sphere A solid having the shape of a ball is called a sphere. [Figure 3-28] A sphere has a constant diameter. The radius (r) of a sphere is one-half of the diameter (d). The formula for the volume of a sphere is given as: *Figure 3-23. Applied mathematics formula sheet.* Figure/table content: Length | Area 1 inch | 2.54 centimeters | 25.4 millimeters | 1 square inch | 6.45 square centimeters 1 foot | 12 inches | 30.48 centimeters | 1 square foot | 144 square inches | 0.093 square meters 1 yard | 3 feet | 0.9144 meters | 1 square yard | 9 square feet | 0.836 square meters 1 mile | 5,280 feet | 1,760 yards | 1 acre | 43,560 square feet 1 millimeter | 0.0394 inches | 1 square mile | 640 acres | 2.59 square kilometers 1 kilometer | 0.62 miles | 1 square centimeter | 0.155 square inches 1 square meter | 1.195 square yards 1 square kilometer | 0.384 square miles 1 fluid ounce | 29.57 cubic centimeters 1 cup | 8 fluid ounces 1 pint | 2 cups | 16 fluid ounces | 0.473 liters 1 quart | 2 pints | 4 cups | 32 fluid ounces | 0.9463 liters 1 gallon | 4 quarts | 8 pints | 16 cups | 128 ounces | 3.785 liters 1 gallon | 231 cubic inches 1 liter | 0.264 gallons | 1.057 quarts 1 cubic foot | 1,728 cubic inches | 7.5 gallons 1 cubic yard | 27 cubic feet 1 board foot | 1 inch x 12 inches x 12 inches Weight | Temperature 1 ounce | 28.350 grams | °F to °C | Celsius = ⁵⁄9 × (°F − 32) 1 pound | 16 ounces | 453.592 grams 0.4536 kilograms | °C to °F | Fahrenheit = ⁹⁄5 × (°C + 32) 1 ton | 2,000 pounds 1 milligram | 0.001 grams 1 kilogram | 1,000 grams | 2.2 pounds 1 gram | 0.0353 ounces Figure labels: Volume [General p. 3-23] ### Order of Operation for Algebraic Equations ### Trigonometric Equations ### Pythagorean Theorem v = 4⁄3 × π × radius3 = 4⁄3 × π × r3 or v = 1⁄6 × πd3 Example: A pressure tank inside the fuselage of a cargo aircraft is in the shape of a sphere with a diameter of 34 inches. What is the volume of the pressure tank? v = 4⁄3 × π × radius3 = 4⁄3 × (3.1416) × (34⁄2)3 = 1.33 × 3.1416 × 173 = 1.33 × 3.1416 × 4,913 v = 20,528.125 cubic inches ### Cone A solid with a circle as a base and with sides that gradually taper to a point is called a cone. [Figure 3-29] The formula for the volume of a cone is given as: v = 1⁄3 × π × radius2 × height = 1⁄3 × π × r2 × h ### Units of Volume Since all volumes are not measured in the same units, it is necessary to know all the common units of volume and how they are related to each other. For example, the mechanic may know the volume of a tank in cubic feet or cubic inches, but when the tank is full of gasoline, they are interested in how many gallons it contains. Refer to Figure 3-23, Applied Mathematics Formula Sheet, for a comparison of different units of volume. ## Computing Surface Area of Three- Dimensional Solids The surface area of a three-dimensional solid is the sum of the areas of the faces of the solid. Surface area is a different *Figure 3-23. Applied mathematics formula sheet (continued).* *Figure 3-24. Rectangular solid.* *Figure 3-25. Cube.* Figure labels: 1. Parentheses; 2. Exponents; 3. Multiplication; 4. Division; 6. Subtraction; Use the acronym PEMDAS to remember the order of; operation in algebra. PEMDAS is an acronym for parentheses,; exponents, multiplication, division, addition, and subtraction.; To remember it, many use the sentence, “Please Excuse My; Dear Aunt Sally.”; Sine (sin) of angle A =opposite side (side a); hypotenuse (side c); Cosine (cos) of angle A =adjacent side (side b); Tangent (tan) of angle A =opposite side (side a); adjacent side (side b); a2 + b2 = c2; 5. Addition; L = 3 [General p. 3-24] concept from that of volume. For example, surface area is the amount of sheet metal needed to build a rectangular fuel tank while volume is the amount of fuel that the tank can contain. ### Rectangular Solid The formula for the surface area of a rectangular solid [Figure 3-24] is given as: Surface area = 2 × [(width × length) + (width × height) + (length × height)] = 2 × [(w × l) + (w × h) + (l × h)] ### Cube The formula for the surface area of a cube [Figure 3-25] is given as: Surface area = 6 × (side × side) = 6 × s2 Example: What is the surface area of a cube with a side measure of 8 inches? Surface area = 6 × (side × side) = 6 × S2 = 6 × 82 = 6 × 64 = 384 square inches ### Cylinder The formula for the surface area of a cylinder [Figure 3-26] is given as: Surface area = 2 × π × radius2 + π × diameter × height = 2 × π × r2 + π × d × h ### Sphere The formula for the surface area of a sphere [Figure 3-28] is given as: Surface area = 4 × π × radius2 = 4 × π × r2 ### Cone The formula for the surface area of a right circular cone [Figure 3-29] is given as: Surface area = π × radius × [radius + √(radius2 + height2)] = π × r × [r + √(r2 + h2)] Figure 3-30 summarizes the formulas for computing the volume and surface area of three-dimensional solids. ## Trigonometric Functions Trigonometry is the study of the relationship between the angles and sides of a triangle. The word trigonometry comes from the Greek trigonon, which means three angles, and metro, which means measure. ### Right Triangle, Sides, and Angles In Figure 3-31, notice that each angle is labeled with a capital letter. Across from each angle is a corresponding side, each labeled with a lower case letter. This triangle is a right triangle because angle C is a 90° angle. Side “a” is *Figure 3-26. Cylinder.* *Figure 3-27. Cylinder displacement.* Figure labels: piston; cylinder; diameter; bore; Piston at top center; Piston at bottom center [General p. 3-25] opposite from angle A and is sometimes referred to as the “opposite side.” Side “b” is next to, or adjacent to, angle A and is therefore referred to as the “adjacent side.” Side “c” is always across from the right angle and is referred to as the “hypotenuse.” ### Sine, Cosine, and Tangent The three primary trigonometric functions and their abbreviations are: sine (sin), cosine (cos), and tangent (tan). These three functions can be found on most scientific calculators. The three trigonometric functions are actually ratios comparing two of the sides of the triangle as follows: Sine (sin) of angle A = opposite side (side a) hypotenuse (side c) Cosine (cos) of angle A = adjacent side (side b) hypotenuse (side c) Tangent (tan) of angle A = opposite side (side a) adjacent side (side b) Example: Find the sine of a 30° angle. ## Calculator Method: Using a calculator, select the “sin” feature, enter the number 30, and press “enter.” The calculator should display the answer as 0.5. This means that when angle A equals 30°, then the ratio of the opposite side (a) to the hypotenuse (c) equals 0.5 to 1, so the hypotenuse is twice as long as the opposite side for a 30° angle. Therefore, sin 30° = 0.5. ## Trigonometry Table Method: When using a trigonometry table, find 30° in the first column. Next, find the value for sin 30° under the second column marked “sine” or “sin.” The value for sin 30° should be 0.5. ### Pythagorean Theorem The Pythagorean Theorem is named after the ancient Greek mathematician, Pythagoras (~500 B.C.). This theorem is used to find the third side of any right triangle when two sides are known. The Pythagorean Theorem states that a2 + b2 = c2. [Figure 3-32] Where “c” = the hypotenuse of a right triangle, “a” is one side of the triangle and “b” is the other side of the triangle. Example: What is the length of the longest side of a right triangle, given the other sides are 7 inches and 9 inches? The longest side of a right triangle is always side “c,” the hypotenuse. Use the Pythagorean Theorem to solve for the length of side “c” as follows: a2 + b2 = c2 72 + 92 = c2 49 + 81 = c2 130 = c2 c = 130 = 11.4 inches Therefore, side “c” = 11.4 inches. Example: The cargo door opening in a military airplane is a rectangle that is 51⁄2 feet tall by 7 feet wide. A section of square steel plate that is 8 feet wide by 8 feet tall by 1 inch thick must fit inside the airplane. Can the square section of steel plate fit through the cargo door? It is obvious that the square steel plate will not fit horizontally through the cargo door. The steel plate is 8 feet wide and the cargo door is only 7 feet wide. However, if the steel plate is tilted diagonally, will it fit through the cargo door opening? The diagonal distance across the cargo door opening can be calculated using the Pythagorean Theorem where “a” is the cargo door width, “b” is the cargo door height, and “c” is the diagonal distance across the cargo door opening. a2 + b2 = c2 *Figure 3-28. Sphere.* *Figure 3-29. Cone.* [General p. 3-26] (7 ft)2 + (5.5 ft)2 = c2 49 + 30.25 = c2 79.25 = c2 c = 8.9 ft The diagonal distance across the cargo door opening is 8.9 feet, so the 8-foot wide square steel plate fits diagonally through the cargo door opening and into the airplane. ## Measurement Systems ### Conventional (U.S. or English) System Our conventional (U.S. or English) system of measurement is part of our cultural heritage from the days when the thirteen colonies were under British rule. It started as a collection of Anglo-Saxon, Roman, and Norman-French weights and measures. For example, the inch represents the width of the thumb and the foot is from the length of the human foot. Tradition holds that King Henry I decreed that the yard should be the distance from the tip of his nose to the end of his thumb. Since medieval times, commissions appointed by various English monarchs have reduced the chaos of measurement by setting specific standards for some of the most important units. Some of the conventional units of measure are: inches, feet, yards, miles, ounces, pints, gallons, and pounds. Because the conventional system was not set up systematically, it contains a random collection of conversions. For example, 1 mile = 5,280 feet and 1 foot = 12 inches. ### Metric System The metric system, also known as the International System of Units (SI), is the dominant language of measurement used today. Its standardization and decimal features make it well-suited for engineering and aviation work. The metric system was first envisioned by Gabriel Mouton, Vicar of St. Paul’s Church in Lyons, France. The meter is the unit of length in the metric system, and it is equal to one ten-millionth of the distance from the equator to the North Pole. The liter is the unit of volume and is equal to one cubic decimeter. The gram is the unit of mass and is equal to one cubic centimeter of water. All of the metric units follow a consistent naming scheme, which consists of attaching a prefix to the unit. For example, since kilo stands for 1,000, one kilometer equals 1,000 meters. Centi is the prefix for one hundredth, so one meter equals one hundred centimeters. Milli is the prefix for one thousandths and one gram equals one thousand milligrams. Refer to Figure 3-33 for the names and definitions of metric prefixes. ### Measurement Systems & Conversions The United States primarily uses the conventional (U.S. or English) system, although it is slowly integrating the metric system (SI). A recommendation to transition to the metric system within ten years was initiated in the 1970s. However, this movement lost momentum, and the United States continues to use both measurement systems. Therefore, information to convert between the conventional (U.S. or English) system and the metric (SI) system has been included in Figure 3-23, Applied Mathematics Formula Sheet. Examples of its use are as follows: To convert inches to millimeters, multiply the number of inches by 25.4. Example: 20 inches = 20 × 25.4 = 508 mm To convert ounces to grams, multiply the number of ounces by 28.35. Example: 12 ounces = 12 × 28.35 = 340.2 grams *Figure 3-30. Formulas to compute volume and surface area.* *Figure 3-31. Right triangle.* *Figure 3-32. Pythagorean Theorem.* Figure/table content: Solid | Volume | Surface Area | Figure Rectangle | l × w × h | 2 × [(w × l) + (w × h) + | 3-24 Solid | (l × h)] Cube | s3 | 6 × s2 | 3-25 Cylinder | π × r2 × h | 2 × π × r2 + π × d × h | 3-26 Sphere | ⁴⁄3 × π × r3 | 4 × π × r2 | 3-28 Cone | ¹⁄3 × π × r2 × h | π × r × [r + √(r2 + h2)] | 3-29 Figure labels: a2 + b2 = c2 [General p. 3-27] ## The Binary Number System The binary number system has only two digits: 0 and 1. The prefix in the word “binary” is a Latin root for the word “two” and its use was first published in the late 1700s. The use of the binary number system is based on the fact that switches or valves have two states: open or closed (on/off). Currently, one of the primary uses of the binary number system is in computer applications. Information is stored as a series of 0s and 1s, forming strings of binary numbers. An early electronic computer, ENIAC (Electronic Numerical Integrator and Calculator), was built in 1946 at the University of Pennsylvania and contained 17,000 vacuum tubes, along with 70,000 resistors, 10,000 capacitors, 1,500 relays, 6,000 manual switches and 5 million soldered joints. Computers obviously have changed a great deal since then, but are still based on the same binary number system. The binary number system is also useful when working with digital electronics because the two basic conditions of electricity, on and off, can be represented by the two digits of the binary number system. When the system is on, it is represented by the digit 1, and when it is off, it is represented by the digit 0. ### Place Values The binary number system is a Base-2 system. That is, the place values in the binary number system are based on powers of 2. An 8-bit binary number system is shown in Figure 3-34. ### Converting Binary Numbers to Decimal Numbers To convert a binary number to a decimal number, add up the place values that have a 1 (place values that have a zero do not contribute to the decimal number conversion). Example: Convert the binary number 10110011 to a decimal number. Using the place value chart in Figure 3-35, add up the place values of the ‘1s’ in the binary number (ignore the place values with a zero in the binary number). The binary number 10110011 = 128 + 0 + 32 + 16 + 0 + 0 + 2 + 1 = 179 in the decimal number system ### Converting Decimal Numbers to Binary Numbers To convert a decimal number to a binary number, the place values in the binary system are used to create a sum of numbers that equal the value of the decimal number being converted. Start with the largest binary place value and subtract from the decimal number. Continue this process until all of the binary digits are determined. Example: Convert the decimal number 233 to a binary number. Start by subtracting 128 (the largest place value from the 8-bit binary number) from 233. 233 – 128 = 105 A “1” is placed in the first binary digit space: 1XXXXXXX. Continue the process of subtracting the binary number place values: 105 – 64 = 41 A “1” is placed in the second binary digit space: 11XXXXXX. 41 – 32 = 9 A “1” is placed in the third binary digit space: 111XXXXX. *Figure 3-33. Names and definitions of metric prefixes.* Figure/table content: Multiplier | Multiplier Symbol | Prefix | Meaning (Exponential) | (Numerical) exa | (1018) | 1,000,000,000,000,000,000 | quintillion peta | (1015) | 1,000,000,000,000,000 | quadrillion tera | (1012) | 1,000,000,000,000 | trillion giga | (109) | 1,000,000,000 | billion mega | (106) | 1,000,000 | million kilo | (103) | 1,000 | thousand hecto | (102) | hundred da | deca | (101) | ten unit | Less Than 1 deci | (10−1) | tenth centi | (10−2) | 0.01 | hundredth milli | (10−3) | 0.001 | thousandth µ | micro | (10−6) | 0.000,001 | millionth nano | (10−9) | 0.000,000,001 | billionth pico | (10−12) | 0.000,000,000,001 | trillionth femto | (10−15) | 0.000,000,000,000,001 | quadrillionth atto | (10−18) | 0.000,000,000,000,000,001 | quintillionth Figure labels: Greater Than 1 [General p. 3-28] Since 9 is less than 16 (the next binary place value), a “0” is placed in the fourth binary digit space, 1110XXXX. 9 – 8 = 1 A “1” is placed in the fifth binary digit space: 11101XXX Since 1 is less than 4 (the next binary place value), a 0 is placed in the sixth binary digit space: 111010XX. Since 1 is less than 2 (the next binary place value), a 0 is placed in the seventh binary digit space: 1110100X. 1 – 1 = 0 A “1” is placed in the eighth binary digit space: 11101001. The decimal number 233 is equivalent to the binary number 11101001, as shown in Figure 3-36. Three additional decimal number to binary number conversions are shown in Figure 3-36. *Figure 3-34. Binary system.* *Figure 3-35. Place value chart.* *Figure 3-36. Conversion from decimal number to binary number.* Figure/table content: or 128 | or 64 | or 32 | or 16 | or 8 | or 4 | or 2 | or 1 10011001 shown as | =153 or 128 | or 64 | or 32 | or 16 | or 8 | or 4 | or 2 | or 1 or 128 | or 64 | or 32 | or 16 | or 8 | or 4 | or 2 | or 1 Figure labels: Place Value; 00101011 shown as; 10110011 shown as; =179; 35 shown as; 124 shown as; 96 shown as; 255 shown as; 233 shown as